here is some food for thought tho on how I will be deriving the motion energy's involved
because the system described on the other page is just the rest Mass of the system
I still have to describe the nuclear motion
and the electronic motion that will add to the mass
So i will simulate the model as if all the electrons and positrons
just appeared in this type of configuration ... and I believe that is the best way to simulate it since then the simulation will have real meaning not just pre-plotted courses , then the physics can take over.
if you look at the (Neutron Mass - Proton Mass)= [epe]
ProtonMass = 1.6726231*10^-27
NeutronMass = 1.6749286*10^-27
(Neutron Mass - Proton Mass)= 2.3055*10^-30
2.3055*10^-30 - (9.1093897*10^-31) - (9.1093897*10^-31) = 4.8362206*10^-31
*Reduced Electron Mass = 4.55469485*10^-31
(4.55469485*10^-31)-(4.862206*10^-31) = Motion Energy
So if this theory is correct then the Motion energy should be LESS THAN 2.8152575*10^-32
this is A little high based on the projected Proton energy motion of 2.02243*10^-32 per each 729
of 2187 or (1.47435*10^-29 Total)
this is because just one of the "Quarks" the center one is changed form
pep epe pep
epe pep epe = 2 of V
pep epe pep
to
pep epe pep
epe(pep)epe = 2 of V = V`
(((((epe))))
pep epe pep
so that V has more repulsion going on then a normal V
which is = to (2.8152575*10^-32 - 2.02243*10^-32)
So granted that the overall repulsions makes the mass look like there is both the epe and the pep in the center,
the overall forces could make the neutron 2 of V able to do that
because of the overall forces acting inward toward the center
Geometrically this could decay into a proton as you can see!
That will be determined by the Mathematics of physics tho
so I will be testing this theory shortly to determine if my thoughts are correct by simulating it.
ElectronMass = 9.1093897*10^-31
ElectronMass + ElectronMass + Reduced ElectronMass = (Neutron Mass - Proton Mass)
Reduced ElectronMass = (Mass a * Mass b)*(Mass a + Mass b)^-1
NOTE BY SAYING REDUCED ELECTRON MASS I ALSO MEAN REDUCED POSITRON MASS -- FOR THE CENTER
electron or positron in [e(p)e] or [p(e)p]
you can take a look at the Animated simulation of epe at
the code for Mathematica 6.3 is
Animate[Graphics[{Circle[], Point[{.43*Cos[t 4 - Pi], -.43*Sin[t ]}], Point[{-.43*Cos[t 4 - Pi], .43*Sin[t ]}], Point[{-.02*Cos[t 4 ], -.02*Sin[t ]}]}], {t, -11, Infinity^11}]
MARX
MARX
