Gravitons and Push Gravity question.

<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by rousejohnny</i>
<br />The issue I asked initially about the person in a pocket within the earth and why that person would weigh more in the pocket than they do on the surface is what I am trying to confront.<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">Okay, that's an interesting question, but has nothing to do with pushing vs. pulling gravity, or with compressed graviton streams, or hula hoops, or anything else you mentioned.

As you descend down an elevator into the Earth, less mass is below you and some mass appears above you, tending to make you weigh less. But you are also drawing closer to the much larger mass below you, and the shrinking distance to the big mass increases the force of gravity inversely with the square of your distance from Earth's center, tending to make you weigh more.

As you descend inside the real Earth, the second factor dominates the first factor for a while because the interior mass is denser than the mass appearing above you. However, there eventually comes a point where the effects balance, and for the rest of the way down to the center, you lose weight.

<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote">Let's use gravitons that are pushing towards the center of gravity. As they push towards the center of the earth they maintain their quantity, what changes is the area in which they occupy is decreasing and the gravitons are being compressed following the inverse square law all the way to the bottom.<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">As you will see from my previous explanation, this is wrong. The identical rules apply, just as I explained above. Each matter ingredient that appears above you exerts a force that tends to make you lighter, whereas drawing closer to the matter ingredients below you tends to make you heavier.

<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote">The number of gravitons attracted to the center of gravity is based on the size of the mass attracting them.<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">There are no "gravitons attracted to the center of gravity". All matter ingredients operate independently of each other. The net of countless zillions of individual small forces is a large net force toward the center. But that net approaches zero as one approaches the center, so none of the graviton wind blowing down on Earth's surface reaches its center. -|Tom|-

<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote">There are no "gravitons attracted to the center of gravity". All matter ingredients operate independently of each other. The net of countless zillions of individual small forces is a large net force toward the center. But that net approaches zero as one approaches the center, so none of the graviton wind blowing down on Earth's surface reaches its center. -|Tom|-

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If it doesn't reach the center, then why would my weight on earth be lighter than on a neutron star....I thought more were being blocked from below that from above implying some of the graviton wind is blowing down though the center and out the otherside....totally confussed now.

For that matter why not eliminate gravitons all together, why don't we say that matter at any grid coordinate in space has a magnetic relationship with all other matter which shows up as gravity. The relationship could be that all particles of mass have an individual relationship will all other particles of mass in which polarity is generated between each set.

rousejohnny,

See if this helps ...

Assume a spherical mass -

* Gravitons travel in all direction at all times.
* They are not "attracted" to mass, but all masses have a large number of gravitons passing through them at all times.
* A small fraction of the gravitons passing through a particular mass will be absorbed or deflected by the mass.
* Gravitons that just happen to pass through the center of the mass are more likely to be absorbed/deflected than gravitons that just happen to graze the surface of the mass, simply because a spherical mass is thickest at the center.
* For spherical masses, this results in the "weakest graviton wind direction" comming from the center of the mass.
* The graviton wind from all other directions is stronger.

There is more to it of course, but this may be enough clues for you to see where your problem is. If not, let me know.

LB

Hmmm. Another way to look at this phenomenon -

The graviton wind blows from *all directions* at *all times*.

Near another mass the wind blowing from the center is weaker than the wind blowing from any other direction. So there is a net force toward the center.

Away from any other mass the graviton wind blows from all directions with the same strength, so the net force is zero.

LB

<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by Larry Burford</i>
<br />Hmmm. Another way to look at this phenomenon -

The graviton wind blows from *all directions* at *all times*.

Near another mass the wind blowing from the center is weaker than the wind blowing from any other direction. So there is a net force toward the center.

Away from any other mass the graviton wind blows from all directions with the same strength, so the net force is zero.

LB

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I have done some reading up....imagine that and I am struck by the fact that if a hole was dug through the earth your acceleration would decrease. Has there ever been an experiment that shows this? Or is this one of those "conventional wisdom" issues that has never been confronted. Does anyone have a link to an experiment. I find it difficult to accept.

<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by rousejohnny</i>
<br />I am struck by the fact that if a hole was dug through the earth your acceleration would decrease. ... I find it difficult to accept.<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">What puzzles you about this? Less mass below means you weigh less. Why is there even a question?

<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote">Has there ever been an experiment that shows this?<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">No, no one has ever dug a hole through the Earth. [] And the amount of mass removed would be trivial compared with Earth's mass anyway, so the miniscule effect is only theoretical. -|Tom|-